a+b/2ab

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a+b/2aba+b/2aba+b/2ab因为a+b≥2√(ab),则:1/(a+b)≤1/[2√(ab)],所以:2ab/(a+b)≤2ab/[2√(ab)]=√ab,即:2ab/[a+b]≤√(a

a+b/2ab
a+b/2ab<根号ab求证

a+b/2ab
因为a+b≥2√(ab),则:1/(a+b)≤1/[2√(ab)],所以:
2ab/(a+b)≤2ab/[2√(ab)]=√ab,即:2ab/[a+b]≤√(ab)

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