化简{sin(π+α)^3cos(-α)cos(π+α)}/{tan(π+α)^3cos(-π-α)^2}

来源:学生作业帮助网 编辑:作业帮 时间:2019/07/16 12:38:36
化简{sin(π+α)^3cos(-α)cos(π+α)}/{tan(π+α)^3cos(-π-α)^2}化简{sin(π+α)^3cos(-α)cos(π+α)}/{tan(π+α)^3cos(-π

化简{sin(π+α)^3cos(-α)cos(π+α)}/{tan(π+α)^3cos(-π-α)^2}
化简{sin(π+α)^3cos(-α)cos(π+α)}/{tan(π+α)^3cos(-π-α)^2}

化简{sin(π+α)^3cos(-α)cos(π+α)}/{tan(π+α)^3cos(-π-α)^2}
原式=(-sin³α)cosα(-cosα)/(tan³α)cos²α
=sin³α/tan³α
=sin³α/(sin³α/cos³α)
=cos³α