1/x

来源:学生作业帮助网 编辑:作业帮 时间:2017/11/24 09:50:44
x/x+(1-x)/x-1/x

x/x+(1-x)/x-1/xx/x+(1-x)/x-1/xx/x+(1-x)/x-1/xx/[x+(1-x)/(x-1/x)]=x/[x+(1-x)/((x²-1)/x)]=x/[x+x(

填九宫格帮帮忙.x x 6 x x 7 x x 98 x x x 3 x 1 x x 9 x x 6 x 5 x 3 x x x 3 x x x x 1 8x x x 9 x 1 x x x2 1 x x x x 6 x x x 6 x 7 x 3 x x 1 x x 9 x 2 x x x 47 x x 8 x x 5 x x

填九宫格帮帮忙.xx6xx7xx98xxx3x1xx9xx6x5x3xxx3xxxx18xxx9x1xxx21xxxx6xxx6x7x3xx1xx9x2xxx47xx8xx5xx填九宫格帮帮忙.xx6

七年级下册政治复习提纲(山东人民出版社)第五单元是 青春的脚步 青春的气息别弄错了啊!格式:X X X X X X X X X 1、X X X X X X X X X X.2、X X X X X X X X X.3、X X X X X X X X X X X.

七年级下册政治复习提纲(山东人民出版社)第五单元是青春的脚步青春的气息别弄错了啊!格式:XXXXXXXXX1、XXXXXXXXXX.2、XXXXXXXXX.3、XXXXXXXXXXX.七年级下册政治复

(x+1)(x-1)(x-x+1)(x+x+1)

(x+1)(x-1)(x-x+1)(x+x+1)(x+1)(x-1)(x-x+1)(x+x+1)(x+1)(x-1)(x-x+1)(x+x+1)(x+1)(x-1)(x-x+1)(x+x+1)=(x^

分解因式----(X*X-X)(X*X-X-2)+1

分解因式----(X*X-X)(X*X-X-2)+1分解因式----(X*X-X)(X*X-X-2)+1分解因式----(X*X-X)(X*X-X-2)+1(x-x)(x-x-2)+1=x(x-1)[

X(X-1)=X

X(X-1)=XX(X-1)=XX(X-1)=XX(X-1)=Xx(x-1)-x=0x(x-1-1)=0x(x-2)=0x1=0,x2=2x∧2-2x=0(x-2)*x=0x=0x=2x(x-1+1)

1.1/x|x/(x+1)|

1.1/x|x/(x+1)|1.1/x|x/(x+1)|1.1/x|x/(x+1)|1,x>1或x

x/x-1[1+(x-1/x)]

x/x-1[1+(x-1/x)]x/x-1[1+(x-1/x)]x/x-1[1+(x-1/x)](2x+1)/(x-1)

x-1/x÷(x-1/x)

x-1/x÷(x-1/x)x-1/x÷(x-1/x)x-1/x÷(x-1/x)(x+1)/[(x2-1)/x〕x(x+1)/(x+1)(x-1)1/x÷(x-1/x)分子分母同×x得到1/(xx-1)

】x(x+1)+x^2(x-1)

】x(x+1)+x^2(x-1)】x(x+1)+x^2(x-1)】x(x+1)+x^2(x-1)x(x+1)+x^2(x-1)=x^2+x+x^3-x^2=x+x^3

1/(1-x)+1/(1+x)+2/(1+x*x)+4/(1+x*x*x*x)+8/(1-x*x*x*x*x*x*x*x)怎么做

1/(1-x)+1/(1+x)+2/(1+x*x)+4/(1+x*x*x*x)+8/(1-x*x*x*x*x*x*x*x)怎么做1/(1-x)+1/(1+x)+2/(1+x*x)+4/(1+x*x*x

x>1/1-x

x>1/1-xx>1/1-xx>1/1-xx>1/1-xx(1-x)/(1-x)>1/(1-x)x(1-x)/(1-x)-1/(1-x)>0(x-x²-1)/(1-x)>0(x²-

x+1/x-1

x+1/x-1x+1/x-1x+1/x-1可用根轴法得-1到1

(X + 1) /(x - 1)

(X+1)/(x-1)(X+1)/(x-1)(X+1)/(x-1)(X+1)/(x-1)(X+1)/(x-1)(X+1)/(x-1)-1(X+1)/(x-1)-(x-1)/(x-1)(X+1-x+1)

(1+X)/(1-X)

(1+X)/(1-X)(1+X)/(1-X)(1+X)/(1-X)(字有点丑不要介意.)小于-1大于1x=±1-1小于-1或者大于1-1<x<1

|x+1|+|x-1|

|x+1|+|x-1||x+1|+|x-1||x+1|+|x-1|x<-1时,-x-1-x+1≤1,x≥-1/2,此时无解-1≤x<1时,x+1-x+1=2,此时无解x≥1时,x+1+x-1≤1,x≤

/X-3/-/X-1/

/X-3/-/X-1//X-3/-/X-1/什么是零点分段法?/X-3/-/X-1/零点分段法就是用函数的零点把数轴分成若干段,逐段讨论的解题方法.如本题中用x=1,x=3把数轴分成三段.(1).x原

化简|x+1/x|

化简|x+1/x|化简|x+1/x|化简|x+1/x|(1).0<x<1,x≠0,Ix+1/xI=x+1/x.(2).x>1,x≠0,Ix+1/xI=x+1/x.(3).0>x>-1,x≠0,Ix+1

x-1/x-2

x-1/x-2x-1/x-2x-1/x-2当x>2时,x-1<2x-4,x>3,所以x>3当x<2时,x-1>2x-4,x<3,所以x<2综上所述,该不